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CとBを結ぶと∠ACB＝90、∠CBA＝∠CDA＝48(円周角なので)となります
∠CAB＝180－90－48
＝42(△ABCの内角の和は180だから)
今度は△ACEをみます
すると∠CEA＝180－82－42＝56
56°
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