✨ Best Answer ✨
a(a^3-12a^2+48a-64)
=a[(a^3-64)-12a(a-4)]
=a[(a-4)(a^2+4a+16)-12a(a-4)]
=a[(a-4)(a^2+4a+16-12a)]
=a(a-4)(a^2-8a+16)
=a(a-4)(a-4)^2
=a(a-4)^3
間違ってたらすいません!
✨ Best Answer ✨
a(a^3-12a^2+48a-64)
=a[(a^3-64)-12a(a-4)]
=a[(a-4)(a^2+4a+16)-12a(a-4)]
=a[(a-4)(a^2+4a+16-12a)]
=a(a-4)(a^2-8a+16)
=a(a-4)(a-4)^2
=a(a-4)^3
間違ってたらすいません!
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