∠DPC=a(平行線の同位角)
∠DCP=90 - a/2(△ABCは二等辺三角形)
外角の定理より
∠APD=a + 90 - a/2 =90 + a/2
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∠DPC=a(平行線の同位角)
∠DCP=90 - a/2(△ABCは二等辺三角形)
外角の定理より
∠APD=a + 90 - a/2 =90 + a/2
Users viewing this question
are also looking at these questions 😉
