-27π/8=-(3π+ 3π/8)なので
第二象限にくるので-になります
同様に-40π/7=-(5π+ 5π/7)なので
第一象限にくるので+になります
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数2三角関数の相互関係
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-27π/8=-(3π+ 3π/8)なので
第二象限にくるので-になります
同様に-40π/7=-(5π+ 5π/7)なので
第一象限にくるので+になります
Users viewing this question
are also looking at these questions 😉